For all numbers x such that $$x \neq 1$$, if g(x) is defined by $$g(x)={{x^2+2}\over{x-1}}$$, then ($${{1}\over{g(2)}}$$)($${{1}\over{g(x)}})$$=?
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A$${{6(x-1)}\over{x^2}}+2$$
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B$${6({x^2+2})\over{x}}-1$$
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C$$(x^2+2)2(x-1)$$
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D$$x-1\over6(x^2+2)$$
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E$$x^2+2\over6(x-1)$$