Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 30 percent ryegrass, what percent of the weight of the mixture is X ?
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A10%
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B$${33}\frac{1}{3}\%$$
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C40%
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D50%
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E$${66}\frac{2}{3}\%$$