Under what conditions is \frac{3x}{\sqrt{-2x^2+6}} not a real number?
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A$$- \sqrt{3} < x < \sqrt{3}$$
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B$$- \sqrt{3} \leq x \leq \sqrt{3}$$
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C$$x \geq \sqrt{3}$$
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D$$ x > \sqrt{3}$$ or $$x < - \sqrt{3}$$
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E$$ x \geq \sqrt{3}$$ or $$x \leq - \sqrt{3}$$
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正确答案: E